You are given:
N colors, numbered from 1 to N.
For each color i, Chef has Ai balls of that color.
Chef will use some boxes.
Each ball must go into exactly one box.
Constraint: No box can contain two balls of the same color.
You must find the minimum number of boxes needed.
Problem Restatement
For each test case:
You know how many balls of each color Chef has.
You must place them into boxes such that:
Each ball goes into exactly one box.
A box can contain multiple balls, but all of different colors.
Goal: Minimize the number of boxes.
Input Format:
First line: T — number of test cases.
For each test case:
First line: N — number of colors.
Second line: N integers A1, A2, ...., An
where Ai is the number of balls of color i.
Output Format:
For each test case, print the minimum number of boxes required.
Constraints:
1 ≤ T ≤ 1000
2 ≤ N ≤ 100
1 ≤ Ai ≤ 105
Sample:
Input:
3
2
8 5
3
5 10 15
4
4 4 4 4
Output:
8
15
4
Explanation:
Test case 1
Colors: 2
Balls: color 1 → 8 balls, color 2 → 5 balls
For color 1 (8 balls): a single box can only contain 1 ball of this color, so we need at least 8 boxes overall, no matter what.
We can arrange as:
5 boxes with [1, 2]
3 boxes with [1]
Total boxes = 8, which matches the maximum count among colors (max(A) = 8).
Test case 2
Balls: [5, 10, 15]
Color counts: 5, 10, 15 → the largest is 15.
You need at least 15 boxes, because the color that appears 15 times must have its balls in 15 distinct boxes.
It is always possible to place other colors into these boxes without violating the rule.
Answer = 15.
Test case 3
Balls: [4, 4, 4, 4]
Each color has 4 balls, so max(A) = 4.
We can use 4 boxes:
Box 1: [1, 2, 3, 4]
Box 2: [1, 2, 3, 4]
Box 3: [1, 2, 3, 4]
Box 4: [1, 2, 3, 4]
No box has two balls of the same color.
So the minimum number of boxes required is 4.
Intuition and Key Observation
In any single box:
You can have at most 1 ball of each color.
Consider some color i with Ai balls:
These Ai balls must be placed in different boxes (since no box can contain two balls of color i).
Therefore, the number of boxes must be at least Ai for each color i.
So, over all colors:
The number of boxes must be at least max(A1, A2, ...., An).
Now the crucial question:
Is it always possible to do it with exactly max(Ai) boxes?
Yes:
Let M = max(Ai).
We create M boxes.
For each color i, place one ball of color i into a different box each time, spreading its Ai balls across at most M boxes.
Since Ai ≤ M for every color, we will never need more than M boxes for any color.
There is no upper limit on how many different colors can be in one box, so this packing is always possible.
Therefore:
Answer = max1 ≤ i ≤ NAi
Approach
Step-by-step:
For each test case:
Read integer N.
Read array A of length N.
Compute the maximum value in A, call it maxA.
Print maxA.
Time & Space Complexity:
Per test case: O(N) to read and find maximum.
Total over all test cases: O(∑N), which is easily within the limits.
Space: O(1) extra (besides the input array).
Pseudocode:
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